(y^2-y+2)(5y-2)=0

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Solution for (y^2-y+2)(5y-2)=0 equation: 


Simplifying
(y2 + -1y + 2)(5y + -2) = 0

Reorder the terms:
(2 + -1y + y2)(5y + -2) = 0

Reorder the terms:
(2 + -1y + y2)(-2 + 5y) = 0

Multiply (2 + -1y + y2) * (-2 + 5y)
(2(-2 + 5y) + -1y * (-2 + 5y) + y2(-2 + 5y)) = 0
((-2 * 2 + 5y * 2) + -1y * (-2 + 5y) + y2(-2 + 5y)) = 0
((-4 + 10y) + -1y * (-2 + 5y) + y2(-2 + 5y)) = 0
(-4 + 10y + (-2 * -1y + 5y * -1y) + y2(-2 + 5y)) = 0
(-4 + 10y + (2y + -5y2) + y2(-2 + 5y)) = 0
(-4 + 10y + 2y + -5y2 + (-2 * y2 + 5y * y2)) = 0
(-4 + 10y + 2y + -5y2 + (-2y2 + 5y3)) = 0

Combine like terms: 10y + 2y = 12y
(-4 + 12y + -5y2 + -2y2 + 5y3) = 0

Combine like terms: -5y2 + -2y2 = -7y2
(-4 + 12y + -7y2 + 5y3) = 0

Solving
-4 + 12y + -7y2 + 5y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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